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Chemistry

Give equations for the reduction of :

(a) Copper oxide

(b) Iron (III) oxide

(c) Lead (II) oxide

(d) Zinc oxide

Metallurgy

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Answer

(a) Reduction of Copper oxide

CuO+C→ΔCu+CO\text{CuO} + \text{C} \xrightarrow{\Delta} \text{Cu} + \text{CO}

CuO+CO→ΔCu+CO2\text{CuO} + \text{CO} \xrightarrow{\Delta} \text{Cu} + \text{CO}_2

CuOblack+H2→ΔCupink/brown+H2O\underset{\text{black}}{\text{CuO}} + \text{H}2 \xrightarrow{\Delta} \underset{\text{pink/brown}}{\text{Cu}} + \text{H}{2}\text{{O}}

(b) Reduction of Iron (III) oxide

Fe2O3+2Al→2Fe+Al2O3+heat\text{Fe}2\text{O}3 + 2\text{Al} \rightarrow \text{2Fe} + \text{Al}2\text{O}3 + \text{heat}

(c) Reduction of Lead (II) oxide

PbO+C→ΔPb+CO\text{PbO} + \text{C} \xrightarrow{\Delta} \text{Pb} + \text{CO}

PbO+CO→ΔPb+CO2\text{PbO} + \text{CO} \xrightarrow{\Delta} \text{Pb} + \text{CO}_2

PbOyellow+H2→ΔPbgreenish white+H2O\underset{\text{yellow}}{\text{PbO}} + \text{H}2 \xrightarrow{\Delta} \underset{\text{greenish white}}{\text{Pb}} + \text{H}{2}\text{{O}}

(d) Reduction of Zinc oxide

ZnO+C→1400°CZn+CO\text{ZnO} + \text{C} \xrightarrow{1400\degree \text{C}} \text{Zn} + \text{CO}

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