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Mathematics

Given 2log10x + 1 = log10250, find

(i) x

(ii) log102x

Logarithms

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Answer

(i) Given,

2log10x + 1 = log10250

⇒ log10x2 + log1010 = log10250

⇒ log10x2 = log10250 - log1010

⇒ log10x2 = log1025010\text{log}_{10}\dfrac{250}{10}

⇒ log10x2 = log1025

⇒ x2 = 25

⇒ x = 5.

Hence, x = 5.

(ii) Given,

log102x

⇒ log102(5) = log1010 = 1.

Hence, log102x = 1.

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