Mathematics
Given 2log10x + 1 = log10250, find
(i) x
(ii) log102x
Logarithms
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Answer
(i) Given,
2log10x + 1 = log10250
⇒ log10x2 + log1010 = log10250
⇒ log10x2 = log10250 - log1010
⇒ log10x2 =
⇒ log10x2 = log1025
⇒ x2 = 25
⇒ x = 5.
Hence, x = 5.
(ii) Given,
log102x
⇒ log102(5) = log1010 = 1.
Hence, log102x = 1.
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