Chemistry
| Group numbers | 1 - IA | 2 - IIA | 13 - IIIA | 14 - IVA | 15 - VA | 16 - VIA | 17 - VIIA | 18 - 0 |
|---|---|---|---|---|---|---|---|---|
| 2nd period | Li | D | O | J | Ne | |||
| 3rd period | A | Mg | E | Si | H | M | ||
| 4th period | R | T | I | Q | u | y |
In the above table, H does not represent hydrogen.
Some elements are in their own symbol and position in the periodic table, while others are shown with a letter.
Identify :
(i) The most electronegative element.
(ii) The most reactive element of group I.
(iii) The element from period 3 with least atomic size.
(iv) The noble gas of the fourth period.
(v) How many valence electrons are present in Q.
(vi) Which element from group 2 would have the least ionization energy?
(vii) In the compound between A and H, what type of bond is formed and give it's molecular formula.
Periodic Table
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Answer
(i) J is the most electronegative element.
(ii) R is the most reactive element of group 1.
(iii) M is the element from period 3 with least atomic size.
(iv) y is the noble gas of the fourth period.
(v) 5 valence electrons present in Q.
(vi) T is the element from group 2 which has least ionization energy.
(vii) ionic bond is formed between A and H.
The molecular formula is :
2A + H ⟶ A2H
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Related Questions
Give reasons for the following:
Atomic size of an element depends on the nuclear charge of that element.
Give reasons for the following:
Down a group electronegativity should increase with increase in nuclear charge but it is seen that the electronegativity decreases.
Give reasons for the following:
If combining atoms have nearly similar electronegativities the bond between them is covalent.
Arrange the following elements as per the guidelines in brackets.
- Na, Cl, Mg, P [in decreasing order of atomic size]
- C, Li, F, N [in increasing order of electronegativity]
- Cl, Al, Na, S [in increasing order of ionization potential]
- Li, F, C, O [in increasing order of electron affinity]
- Ar, He, Ne [in increasing order of number of electron shells]