Height of vertical pole (in cm)	56	672	448	2016
Length of its shadow on a horizontal ground (in cm)	32	a	b	c

It is a case of direct variation:

$\therefore \dfrac{56}{32} = \dfrac{672}{a} = \dfrac{448}{b} = \dfrac{2016}{c}$

Taking,

$\dfrac{56}{32} = \dfrac{672}{a}$

⇒ 56 x a = 672 x 32

⇒ a = $\dfrac{672 \times 32}{56}$

⇒ a = 12 x 32

⇒ a = 384 cm

Taking,

$\dfrac{56}{32} = \dfrac{448}{b}$

⇒ 56 x b = 32 x 448

⇒ b = $\dfrac{32 \times 448}{56}$

⇒ b = 32 x 8

⇒ b = 256 cm

Taking,

$\dfrac{56}{32} = \dfrac{2016}{c}$

⇒ 56 x c = 2016 x 32

⇒ c = $\dfrac{2016 \times 32}{56}$

⇒ c = 36 x 32

⇒ c = 1,152 cm

Hence, the value of a = 384 cm, b = 256 cm and c = 1,152 cm.