How is the current flowing in a conductor changed if the resistance of conductor is doubled keeping the potential difference across it the same?

According to Ohm's law,

$\text{V} = \text{I}\text{R} \\[0.5em] \Rightarrow \text{I} = \dfrac{V}{R} \\[1em]$

Let the doubled resistance be 2R. Potential difference remains the same

$\text{I}_{\text{new}} = \dfrac{V}{2R} \\[0.5em] \Rightarrow \text{I}_{\text{new}} = \dfrac{I}{2}$

∴ If the resistance of conductor is doubled keeping the potential difference across it the same then current flowing in a conductor will be halved.