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Chemistry

(i) Calculate the number of gram atoms in 4.6 grams of sodium (Na = 23).

(ii) Calculate the percentage of water of crystallization in CuSO4.5H2O (H = 1, O = 16, S = 32, Cu = 64)

(iii) A compound of X and Y has the empirical formula XY2. Its vapour density is equal to its empirical formula weight. Determine its molecular formula.

Stoichiometry

ICSE 2017

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Answer

(i) 23 g of Na = 1 g. atom

∴ 4.6 g. of Na = 123\dfrac{1}{23} x 4.6 = 0.2 g

Hence, 0.2 g. atoms

(ii) Molecular weight of hydrated copper sulphate CuSO4.5H2O = 64 + 32 + 4(16) + 5[2(1) + 16]

= 64 + 32 + 64 + 5[18]

= 64 + 32 + 64 + 90

= 250 g

250 g of CuSO4.5H2O contains 90 g of water of crystallization.

∴ Percentage of water of crystallization = 90250\dfrac{90}{250} x 100 = 36%

Hence, percentage of water of crystallization is 36%

(iii) Empirical formula = XY2

Empirical formula weight = V.D.

Molecular weight = 2 x V.D.

n=Molecular weightEmpirical formula weightn=2 x V.D.V.D.n=2\text{n} = \dfrac{\text{Molecular weight}}{\text{Empirical formula weight}} \\[0.5em] \text{n} = \dfrac{\text{2 x V.D.}}{\text{V.D.}} \\[0.5em] \text{n} = 2

∴ Molecular formula = n[E.F.] = 2[XY2] = X2Y4

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