Chemistry
Identify the anion present in each of the following compounds.
(a) Barium chloride on reacting with compound Z will form a white precipitate.
(b) Compound Y on reaction with sulphuric acid will liberate carbon dioxide along with sodium sulphate and water.
Analytical Chemistry
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Answer
(a) SO42- (sulphate)
Reason — White precipitate formed is of barium sulphate [BaSO4], hence anion present is SO42-.
(b) CO32- (carbonate)
Reason — Sodium carbonate will react with sulphuric acid liberate carbon dioxide along with sodium sulphate and water.
Na2CO3 + H2SO4 ⟶ CO2 + Na2SO4 + H2O
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