Given,
(3x - 4y) : (2x - 3y) = (5x - 6y) : (4x - 5y)
⇒2x−3y3x−4y=4x−5y5x−6y⇒(3x−4y)(4x−5y)=(5x−6y)(2x−3y)⇒12x2−15xy−16xy+20y2=10x2−15xy−12xy+18y2⇒12x2−10x2−15xy+15xy−16xy+12xy+20y2−18y2=0⇒2x2−4xy+2y2=0⇒2(x2−2xy+y2)=0⇒x2−2xy+y2=0⇒(x−y)2=0⇒x−y=0⇒x=y⇒yx=1
Hence, x : y = 1 : 1.