Given,
⇒a+ba−b=111⇒11(a−b)=a+b⇒11a−11b=a+b⇒11a−a=b+11b⇒10a=12b⇒a=1012b⇒a=56b.
Substituting value of a in (5a + 4b + 15) : (5a - 4b + 3) we get,
⇒5×56b−4b+35×56b+4b+15⇒6b−4b+36b+4b+15⇒2b+310b+15⇒2b+35(2b+3)⇒15.
Hence, (5a + 4b + 15) : (5a - 4b + 3) = 5 : 1.