Chemistry
If a crop of wheat replaces 30 kg of nitrogen per hectare of soil, what mass of the fertilizer calcium nitrate would be required to replace the nitrogen of a 5-hectare field ?
(at wt. N = 14, O = 16, Ca = 40)
Stoichiometry
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Answer
Molecular weight of Ca(NO3)2
= 40 + 2[14 + 3(16)]
= 40 + 2[14 + 48]
= 40 + 2(62)
= 40 + 124 = 164 g
Total nitrogen that has to be replaced in 5 hectares of land = 30 x 5 = 150 kg = 150 x 103 g
28 g of N is present in 164 g of calcium nitrate
∴ 150 x 103 g of N is present in = x 150 x 103 = 878.57 x 103 g = 878.57 kg
Hence, 878.57 kg of fertilizer will be required
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