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Mathematics

If θ is an acute angle and cosec θ = 5\sqrt{5} find the value of cot θ - cos θ.

Trigonometric Identities

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Answer

sin θ = 1cosec θ=15\dfrac{1}{\text{cosec θ}} = \dfrac{1}{\sqrt{5}},

cos2 θ = 1 - sin2 θ = 1 - (15)2=115=45.\Big(\dfrac{1}{\sqrt{5}}\Big)^2 = 1 - \dfrac{1}{5} = \dfrac{4}{5}.

cos θ = 45\sqrt{\dfrac{4}{5}} = 25\dfrac{2}{\sqrt{5}}.

cot θ = cos θsin θ=2515\dfrac{\text{cos θ}}{\text{sin θ}} = \dfrac{\dfrac{2}{\sqrt{5}}}{\dfrac{1}{\sqrt{5}}} = 2.

cot θ - cos θ=225=2(115)=2(51)5.\text{cot θ - cos θ} = 2 - \dfrac{2}{\sqrt{5}} \\[1em] = 2\Big(1 - \dfrac{1}{\sqrt{5}}\Big) \\[1em] = \dfrac{2(\sqrt{5} - 1)}{\sqrt{5}}.

Hence, the value of cot θ - cos θ = 2(51)5\dfrac{2(\sqrt{5} - 1)}{\sqrt{5}}.

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