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Mathematics

Jaya borrowed ₹50000 for 2 years. The rates of interest for two successive years are 12% and 15% respectively. She repays ₹33000 at the end of first year. Find the amount she must pay at the end of second year to clear her debt.

Compound Interest

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Answer

Principal for first year = ₹50000, rate = 12%.

Interest for first year = 50000×12×1100=600000100\dfrac{50000 \times 12 \times 1}{100} = \dfrac{600000}{100} = ₹6000.

Amount after first year = ₹50000 + ₹6000 = ₹56000.

Money refunded at the end of first year = ₹33000.

Principal for second year = ₹56000 - ₹33000 = ₹23000, rate = 15%.

Interest for second year = 23000×15×1100=345000100\dfrac{23000 \times 15 \times 1}{100} = \dfrac{345000}{100} = ₹3450.

Amount after second year = ₹23000 + ₹3450 = ₹26450.

Hence, Jaya must pay ₹26450 at the end of second year to clear her debt.

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