A bag contains 20 red balls, 12 blue balls and 8 green balls. Three balls are drawn one by one with replacement, the probability that the third ball being green is :

1. $\dfrac{1}{2}$

2. $\dfrac{2}{5}$

3. $\dfrac{1}{5}$

4. 1.8

Below are given the probabilities A, B, C and D of an event. P(A) : $\dfrac{3}{5}$, P(B) : 1.2, P(C) : -1.2 and P(D) = $1\dfrac{2}{3}$. Which of the above values of the probabilities is possible :

1. Event A

2. Event B

3. Event C

4. Event D

Number x is chosen from -3, -2, -1, 0, 1, 2 and 3. Also, x² ≤ 5.

Assertion(A): Probability for x² ≤ 5 is $\dfrac{3}{7}$.

Reason(R): Probability = $\dfrac{\text{Favourable outcomes}}{\text{Total number of outcomes}}$.

1. A is true, R is false.

2. A is false, R is true.

3. Both A and R are true and R is correct reason for A.

4. Both A and R are true and R is incorrect reason for A.

Face cards of spades are remove from the pack of 52 cards and the remaining cards are well shuffled. Then a card is drawn from the pack.

Statement (1): The probability of drawing a face card is $\dfrac{7}{52}$.

Statement (2): Kings, queens and jacks are the three face card and so the total number of face cards in the pack of 52 card is 3 x 4 = 12.

1. Both the statements are true.

2. Both the statements are false.

3. Statement 1 is true, and statement 2 is false.

4. Statement 1 is false, and statement 2 is true.