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Mathematics

A man invests ₹ 46,875 at 4% p.a. compound interest for 3 years. The interest for the 1st year will be:

  1. ₹ 1,785

  2. ₹ 1,587

  3. ₹ 1,875

  4. ₹ 1,758

Compound Interest

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Answer

Given,

P = ₹ 46,875

n = 1 year

r = 4%

By formula,

A=P(1+r100)nA = P\Big(1 + \dfrac{r}{100}\Big)^n

Substituting values we get :

A=46875×(1+4100)1A=46875×(100+4100)A=46875×(104100)A=46875×2625A=48,750.\Rightarrow A = 46875 \times \Big(1 + \dfrac{4}{100}\Big)^1 \\[1em] \Rightarrow A = 46875 \times \Big(\dfrac{100 + 4}{100}\Big) \\[1em] \Rightarrow A = 46875 \times \Big(\dfrac{104}{100}\Big) \\[1em] \Rightarrow A = 46875 \times \dfrac{26}{25} \\[1em] \Rightarrow A = ₹ 48,750.

Compound interest = Final amount - Initial principal

= ₹ 48,750 - ₹ 46,875 = ₹ 1,875.

Hence, option 3 is correct option.

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