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Physics

How much heat is required to convert 500 g of ice at 0°C to water at 0°C? The latent heat of fusion of ice is 330 J g⁻¹.

Calorimetry

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Answer

Given,

m = 500 g

latent heat of fusion of ice (L) = 330 J g⁻¹

Let, required heat be Q.

Then,

Q=mL=500×330=165000 J=165 kJ\text Q = \text {mL} = 500 \times 330 = 165000\ \text J = 165\ \text {kJ}

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