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Mathematics

Pramod deposits ₹ 600 per month in a Recurring Deposit Account for 4 years. If the rate of interest is 8% per year; calculate the maturity value of his account.

Banking

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Answer

Given, P = ₹ 600, n = (4 × 12) = 48 months and r = 8%

I = P×n(n+1)2×12×r100P \times \dfrac{n(n + 1)}{2 \times 12} \times \dfrac{r}{100}

I=600×48×492×12×8100=600×784100=6×784=4704.\therefore I = ₹ 600 \times \dfrac{48 \times 49}{2 \times 12} \times \dfrac{8}{100} \\[1em] = ₹ 600 \times \dfrac{784}{100} \\[1em] = ₹ 6 \times 784 \\[1em] = ₹ 4704.

Sum deposited = P × n = ₹ 600 × 48 = ₹ 28800.

Maturity value = Sum deposited + Interest = ₹ 28800 + ₹ 4704 = ₹ 33504.

The amount that Pramod will get at maturity = ₹ 33504.

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