Mathematics
By taking classes 30 - 40, 40 - 50, 50 - 60, ……………, construct a frequency table for the following data :
| 65 | 34 | 74 | 49 | 52 | 35 |
| 71 | 55 | 61 | 40 | 56 | 38 |
| 52 | 56 | 52 | 33 | 60 | 35 |
| 49 | 37 | 53 | 50 | 44 | 30 |
| 62 | 50 | 47 | 45 | 47 | 50 |
| 63 | 61 | 54 | 58 | 47 | 64 |
| 37 | 38 | 44 | 42 | 47 | 55 |
| 70 | 33 | 75 | 49 | 47 | 30 |
| 60 | 69 |
Also, construct a combined histogram and frequency polygon for the distribution.
Statistics
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Answer
The frequency table for the given distribution is :
| Classes | Tally marks | Frequency |
|---|---|---|
| 30 - 40 | 11 | |
| 40 - 50 | 13 | |
| 50 - 60 | 13 | |
| 60 - 70 | 9 | |
| 70 - 80 | IIII | 4 |
Steps:
1. Draw a histogram.
- On the x-axis, mark the class intervals: 30-40, 40-50, 50-60, 60-70 and 70-80.
- On the y-axis, mark the frequency values.
- Construct rectangles with class-intervals as bases and the corresponding frequencies as heights.
- Since the scale on x-axis starts at 30, a kink (break) or a zig-zag curve is shown near the origin to indicate that the graph is drawn to scale beginning at 30 and not at the origin itself.
2. Mark the mid-points at the top of each rectangle of the histogram drawn.
- 30−40 → 35
- 40−50 → 45
- 50−60 → 55
- 60−70 → 65
- 70−80 → 75
3. Also, mark the mid-point of the immediately lower class-interval ( in the given example, the immediately lower class-interval is 20-30) and mid-point of the immediately higher class-interval (in the given example the immediate upper class-interval is 80-90).
4. Join the consecutive mid-points marked by straight lines to obtain the required frequency polygon.

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