The angles of a pentagon are x°, (x - 10)°, (x + 20)°, (2x - 44)° and (2x - 70)°. Find the value of x.

It is given that the angles of a pentagon are x°, (x - 10)°, (x + 20)°, (2x - 44)° and (2x - 70)°.

According to the properties of a polygon, the sum of the interior angles of a polygon is (2n - 4) x 90°.

For a pentagon, n = 5.

= (2 x 5 - 4) x 90°

= (10 - 4) x 90°

= 6 x 90°

= 540°

So, the sum of the interior angles of the pentagon is 540°.

So,

⇒ x° + (x - 10)° + (x + 20)° + (2x - 44)° + (2x - 70)° = 540°

⇒ x° + x° - 10° + x° + 20° + 2x° - 44° + 2x° - 70° = 540°

⇒ - 104° + 7x° = 540°

⇒ 7x° = 540° + 104°

⇒ 7x° = 644°

⇒ x° = $\dfrac{644°}{7}$

⇒ x° = 92°

Hence, the value of x is 92°.