Mathematics
The class IX students of a certain public school wanted to give a farewell party to the outgoing students of class X. They decided to purchase two kinds of sweets, one costing ₹70 per kg and the other costing ₹84 per kg. They estimated that 36 kg of sweets were needed. If the total money spent on sweets was ₹2800, find how much sweets of each kind they purchased.
Linear Equations
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Answer
Let first sweet purchased be x kg and 2nd be y kg.
Then, x + y = 36 or x = 36 - y …….(i)
Total cost of sweets will be 70x + 84y.
According to question,
⇒ 70x + 84y = 2800
Substituting value of x from (i) in above equation we get,
⇒ 70x + 84(36 - x) = 2800
⇒ 70x + 3024 - 84x = 2800
⇒ 3024 - 14x = 2800
⇒ 14x = 3024 - 2800
⇒ 14x = 224
⇒ x = 16.
Substituting this value of x in eq (i)
⇒ 36 - y = 16
⇒ y = 36 - 16
⇒ y = 20
Hence, the sweet costing ₹70 per kg purchased was 16 kg and the one costing ₹84 per kg was 20 kg.
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