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Mathematics

The following table gives the distribution of students of two sections according to the marks obtained by them:

Section A

MarksFrequency
0 - 103
10 - 209
20 - 3017
30 - 4012
40 - 509

Section B

MarksFrequency
0 - 105
10 - 2019
20 - 3015
30 - 4010
40 - 501

Represent the marks of the students of both the sections on the same graph by two frequency polygons. From the two polygons compare the performance of the two sections.

Statistics

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Answer

Frequency polygons can be drawn independently without drawing histograms. This requires the midpoints of the class intervals used in the data. The mid-points are called class-marks.

Class Mark = Upper limit + Lower limit2\dfrac{\text{Upper limit + Lower limit}}{2}

Substituting the values we get,

Class mark = 10+02=102\dfrac{10 + 0}{2} = \dfrac{10}{2} = 5

Similarly, proceeding in this manner, we get the following table with continuous interval and class mark:

Section A

MarksClass markFrequency
0 - 1053
10 - 20159
20 - 302517
30 - 403512
40 - 50459

Section B

MarksClass markFrequency
0 - 1055
10 - 201519
20 - 302515
30 - 403510
40 - 50451

Steps of construction of frequency polygon :

  1. Take class marks on the x-axis.

  2. Take frequency on the y-axis with an appropriate scale of 1 unit = 2 students.

  3. We draw frequency polygon for section A by plotting the class-marks on x-axis and the frequencies on y-axis, mark the points A(5, 3), B(15, 9), C(25, 17), D(35, 12) and E(45, 9).

  4. We draw a frequency polygon for section B by plotting the class-marks on x-axis and the frequencies on y-axis, marks the points U(5, 5), V(15, 19), W(25, 15), X(35,10) and Y(45, 1).

  5. To complete the polygon, we assume that there is a class interval with frequency zero before the first interval i.e., -10 - 0, and one after the last interval i.e. (50, 60), with class marks -5 and 55 respectively. Mark points G(-5, 0) and Z(55, 0).

  6. Join the points GABCDEZ and GUVWXYZ with the help of different line segments.

  7. Frequency polygon GABCDEZ is formed for Section A.

  8. Frequency polygon GUVWXYZ is formed for Section B.

The following table gives the distribution of students of two sections according to the marks obtained by them: NCERT Class 9 Mathematics CBSE Solutions.

From graph,

We observe that,

The performance of students of Section A is better than the performance of students of Section B, as section A shows more students securing marks between class intervals 30 – 40 and 40 – 50.

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