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Mathematics

The population of a city is 320000. If the annual birth rate is 9.2% and the annual death rate is 1.7%, calculate the population of the town after 3 years.

Compound Interest

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Answer

Net growth rate = 9.2% - 1.7% = 7.5%.

By growth formula,

V = V0(1+r100)nV_0\Big(1 + \dfrac{r}{100}\Big)^n

Putting values in formula we get,

V=320000(1+7.5100)3=320000×(107.5100)3=320000×(10751000)3=320000×(4340)3=320000×4340×4340×4340=320000×7950764000=5×79507=397535.V = 320000\Big(1 + \dfrac{7.5}{100}\Big)^3 \\[1em] = 320000 \times \Big(\dfrac{107.5}{100}\Big)^3 \\[1em] = 320000 \times \Big(\dfrac{1075}{1000}\Big)^3 \\[1em] = 320000 \times \Big(\dfrac{43}{40}\Big)^3 \\[1em] = 320000 \times \dfrac{43}{40} \times \dfrac{43}{40} \times \dfrac{43}{40} \\[1em] \\[1em] = 320000 \times \dfrac{79507}{64000} \\[1em] = 5 \times 79507 \\[1em] = 397535.

Hence, the population of the town after 3 years = 397535.

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