Mathematics
The side AB of an equilateral triangle ABC is parallel to the x-axis. Find the slopes of all its sides.
Straight Line Eq
10 Likes
Answer
Since, AB is parallel to x-axis. It's slope will be equal to the slope of x-axis.
Slope of AB = 0.
We know that,
Angle in equilateral triangle = 60°.
So,
AC is inclined at an angle of 60° from AB so also from x-axis. (As AB || x-axis).
Slope of AC = tan 60° = .
BC is inclined at angle of (180° - 60°) = 120°.
Slope of BC = tan 120° = -.
Hence, slopes of sides of triangle ABC = 0, .
Answered By
9 Likes
Related Questions
A line AB meets X-axis at A and Y-axis at B. P(4, -1) divides AB in the ratio 1 : 2.
(i) Find the co-ordinates of A and B.
(ii) Find the equation of the line through P and perpendicular to AB.
Find the equation of a straight line passing through the intersection of 2x + 5y - 4 = 0 with x-axis and parallel to the line 3x - 7y + 8 = 0.
The line 3x - 4y - 12 = 0 meets x-axis at point A and y-axis at point B.
(i) Find the co-ordinates of the point P on line segment AB dividing AB in the ratio 2 : 1.
(ii) Find the equation of the line that passes through the point P and is perpendicular to AB.
If the lines represented by the equations y + (2p + 1)x + 3 = 0 and 8y - (2p - 1)x = 5 are perpendicular to each other, find p.