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To conduct Sports Day activities, in your rectangular shaped school ground ABCD, lines have been drawn with chalk powder at a distance of 1m each. 100 flower pots have been placed at a distance of 1m from each other along AD, as shown in Fig. 7.12. Niharika runs 14\dfrac{1}{4} th the distance AD on the 2nd line and posts a green flag. Preet runs 15\dfrac{1}{5} th the distance AD on the eighth line and posts a red flag. What is the distance between both the flags? If Rashmi has to post a blue flag exactly halfway between the line segment joining the two flags, where should she post her flag?

To conduct Sports Day activities, in your rectangular shaped school ground ABCD, lines have been drawn with chalk powder at a distance of 1m each. 100 flower pots have been placed at a distance of 1m from each other along AD, as shown in Fig. 7.12. Niharika runs 1/4 th the distance AD on the 2nd line and posts a green flag. Preet runs 1/5 th the distance AD on the eighth line and posts a red flag. What is the distance between both the flags? If Rashmi has to post a blue flag exactly halfway between the line segment joining the two flags, where should she post her flag? NCERT Class 10 Mathematics CBSE Solutions.

Coordinate Geometry

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Answer

Given,

100 flower pots have been placed at a distance of 1 m from each other along AD.

AD = 100 × 1 = 100 m.

It can be observed that Niharika posted the green flag at 14\dfrac{1}{4}th of the distance AD i.e., 14×100=25\dfrac{1}{4} \times 100 = 25 m from the starting point of 2nd line. Therefore, the coordinates of this point G is (2, 25).

Similarly, Preet posted red flag at 15\dfrac{1}{5}th of the distance AD i.e.,15×100=20\dfrac{1}{5} \times 100 = 20 m from the starting point of 8th line. Therefore, the coordinates of this point R are (8, 20).

By formula,

Distance between two points = (y2y1)2+(x2x1)2\sqrt{(y2 - y1)^2 + (x2 - x1)^2}

Substituting values we get :

GR=(2025)2+(82)2=(5)2+(6)2=25+36=61 m.GR = \sqrt{(20 - 25)^2 + (8 - 2)^2} \\[1em] = \sqrt{(-5)^2 + (6)^2} \\[1em] = \sqrt{25 + 36} \\[1em] = \sqrt{61} \text{ m}.

The point at which Rashmi should post her blue flag is the mid-point of the line joining these points. Let this point be A (x, y).

By formula,

Mid-point = (x1+x22,y1+y22)\Big(\dfrac{x1 + x2}{2}, \dfrac{y1 + y2}{2}\Big)

Substituting values we get :

A(x,y)=(2+82,20+252)=(102,452)=(5,22.5)A (x, y) = \Big(\dfrac{2 + 8}{2}, \dfrac{20 + 25}{2}\Big) \\[1em] = \Big(\dfrac{10}{2}, \dfrac{45}{2}\Big) \\[1em] = (5, 22.5)

From figure,

The x-coordinate represets the no. of line and y-coordinate represents the vertical distance.

Hence, Rashmi should post her blue flag at a distance of 22.5m on 5th line.

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