Mathematics
Use proof by contradiction to show that there is no value of n for which 6n ends with the digit zero.
Mathematics Proofs
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Answer
By seeking contradiction,
Let 6n ends with 0.
6n = (2 × 3)n
= 2n × 3n
No value of 2n × 3n can end with zero.
Hence, our assumption is wrong.
Hence, proved that for no value of n, 6n ends with the digit zero.
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