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Mathematics

We have given the timings of the gold medalists in the 400-metre race from the time the event was included in the Olympics, in the table below. Construct a mathematical model relating the years and timings. Use it to estimate the timing in the next Olympics.

YearTiming (in second)
196452.01
196852.03
197251.08
197649.28
198048.88
198448.83
198848.65
199248.83
199648.25
200049.11
200449.41

Mathematical Modelling

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Answer

Let us first convert the problem into a mathematical problem.

Step 1 : Formulation :

Let us take 1964 as 0th year, and write 1 for 1968, 2 for 1972 and so on. So table will be :

YearTiming (in second)
052.01
152.03
251.08
349.28
448.88
548.83
648.65
748.83
848.25
949.11
1049.41

The difference in timings of gold medalist in 400 meters race in Olympics is given in the following table :

YearTiming (in second)Difference
052.010
152.030.02
251.08-0.95
349.28- 1.8
448.88-0.4
548.83-0.05
648.65-0.18
748.830.18
848.25-0.58
949.110.86
1049.410.3
TotalΣDifference = -2.6

At the end of 4 years period from 1964 - 1968 the timing has increased by 0.02 second from 52.01 to 52.03 second.

At the end of second Olympic the reduction in timing is 0.95 second from 52.03 to 51.08. from the table above we cannot find a definite relationship between the number of years and change in timing.

By formula,

Mean difference = Sum of all observationNumber of observation\dfrac{\text{Sum of all observation}}{\text{Number of observation}}

Mean of differences = 2.610\dfrac{-2.6}{10} = -0.26

We have assumed that the timing in 400 m race of Olympic reduced at the rate of 0.26 per year.

So, timing in the first year = 52.01 - 0.26 = 51.75

Timing in the second year = 52.01 - 2 x 0.26 = 52.01 - 5.2 = 51.49

Similarly in the nth year

⇒ t = 52.01 - 0.26 n for n ≥ 1 ……(1)

Now we have to find t for n = 11.

Step 2 : Finding a solution :

Substituting n = 11 in equation (1) we get :

⇒ t = 52.01 - 0.26 x 11

⇒ t = 52.01 - 2.86

⇒ t = 49.15 seconds.

Step 3 : Interpretation :

Since, we are dealing with a real life situation, we have to see to what extent this value matches with the real situation.

Step 4 : Validation :

Let us find the values for the years we already know, using formula/equation (1) and compare it with known values by finding the difference. the values are given in the table :

YearTiming (in second)Timing using equation (1)Deviation
052.0152.010
152.0351.750.28
251.0851.49-0.41
349.2851.23-1.95
448.8850.97-2.09
548.8350.71-1.88
648.6550.45-1.8
748.8350.19-1.36
848.2549.93-1.68
949.1149.67-0.56
1049.4149.410.00
TotalΣ Deviation = -11.45

Suppose we decide that this error is negligible. In this case formula/equation (1) is our mathematical model and if we decide that this error is not acceptable. Then we have to go back to step 1, the formulation and change equation (1).

Step 1 : Reformulation :

We still assume that the values decrease steadily by 0.26, but we will now introduce a correction factor to reduce the error. For this, we find the mean of all the deviations. This is :

Mean deviation=Sum of deviationNo. of observation11.4510=1.145\Rightarrow\text{Mean deviation} = \dfrac{\text{Sum of deviation}}{\text{No. of observation}} \\[1em] \Rightarrow -\dfrac{11.45}{10} = -1.145

We take the mean of the errors and correct our formula by this value.

Step 2 : Revised Mathematical Description :

Let us now add the mean of the deviations to our formula/equation (1). So, our corrected formula is :

⇒ t = 52.01 - 0.26 n - 1.145

⇒ t = 50.865 - 0.26 n ……(2) for n ≥ 1

Step 3 : Altered solution :

By solving equation (2) for t,

Putting n = 1 in equation (2) we get :

⇒ t = 50.865 - 0.26(1)

⇒ t = 50.865 - 0.26 = 50.605

Putting n = 2 in equation (2) we get :

⇒ t = 50.865 - 0.26(2)

⇒ t = 50.865 - 0.52 = 50.345

Putting n = 11 in equation (2) we get :

⇒ t = 50.865 - 0.26(11)

⇒ t = 50.865 - 2.86

⇒ t = 48.005 seconds.

Step 3 : Interpretation :

So in 11th year(in next Olympics) t = 48.005 seconds

Step 4 : Validation :

Once again, let us compare the values got by using formula/equation (2) with the actual values. Table is given below for comparison.

YearTiming (in second)Timing using equation (2)Deviation
052.0152.010
152.0350.6051.425
251.0850.3450.735
349.2850.085-0.805
448.8849.825-0.945
548.8349.565-0.735
648.6549.305-0.655
748.8349.045-0.215
848.2548.785-0.535
949.1148.5250.585
1049.4148.2651.145
TotalΣ Deviation = 0

As we can see many of the values that formula/equation (2) gives are closer to the actual value than the values that formula/equation (1) gives the mean of the deviations is 0. So, formula/equation (2) is our mathematical description that gives a mathematical relationship between years and timing for race.

Hence, timing in next olympics is 48.005 seconds.

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