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Mathematics

cos2θ+11+cot2θ\text{cos}^2 θ + \dfrac{1}{1 + {\text{cot}^2 θ}} = x

Statement (1): x = 1

Statement (2): x = cos2θ+1cosec2θ\text{cos}^2 θ + \dfrac{1}{{\text{cosec}^2 θ}} = cos2 θ + sin2 θ

  1. Both the statement are true.

  2. Both the statement are false.

  3. Statement 1 is true, and statement 2 is false.

  4. Statement 1 is false, and statement 2 is true.

Trigonometric Identities

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Answer

Given, cos2θ+11+cot2θ\text{cos}^2 θ + \dfrac{1}{1 + {\text{cot}^2 θ}} = x

x=cos2θ+11+cot2θx=cos2θ+1cosec2θx=cos2θ+sin2θx=1\Rightarrow x = \text{cos}^2 θ + \dfrac{1}{1 + {\text{cot}^2 θ}}\\[1em] \Rightarrow x = \text{cos}^2 θ + \dfrac{1}{{\text{cosec}^2 θ}}\\[1em] \Rightarrow x = \text{cos}^2 θ + \text{sin}^2 θ\\[1em] \Rightarrow x = 1

∴ Both the statements are true.

Hence, option 1 is the correct option.

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