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Mathematics

A child has a die whose six faces show the letters as given below:

A B C D E A\boxed{A} \space \boxed{B} \space \boxed{C} \space \boxed{D} \space \boxed{E} \space \boxed{A}

The die is thrown once. What is the probability of getting

(i) A?

(ii) D?

Probability

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Answer

There are six faces.

∴ No. of possible outcomes = 6

(i) No. of faces containing A = 6.

∴ No. of favourable outcomes = 2

P(of getting an A) = No. of favourable outcomesNo. of possible outcomes=26=13\dfrac{\text{No. of favourable outcomes}}{\text{No. of possible outcomes}} = \dfrac{2}{6} = \dfrac{1}{3}.

Hence, probability of getting an A = 13\dfrac{1}{3}.

(ii) No. of faces containing D = 1.

∴ No. of favourable outcomes = 1

P(of getting a D) = No. of favourable outcomesNo. of possible outcomes=16\dfrac{\text{No. of favourable outcomes}}{\text{No. of possible outcomes}} = \dfrac{1}{6}.

Hence, probability of getting a D = 16\dfrac{1}{6}.

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