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Mathematics

A man buys a certain number of articles at 15 for ₹ 112.50 and sells them at 12 for ₹ 108. Find :

(i) his gain as percent;

(ii) the number of articles sold to make a profit of ₹ 75.

Profit, Loss & Discount

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Answer

(i) C.P. of 15 articles = ₹ 112.50

C.P. of 1 article = ₹ 112.5015\dfrac{112.50}{15} = ₹ 7.5

S.P. of 12 articles = ₹ 108

S.P. of 1 article = ₹ 10812\dfrac{108}{12} = ₹ 9

(∵ S.P. is greater than C.P., means article is sold at a profit.)

Profit = S.P. - C.P.

= ₹ 9 - ₹ 7.5 = ₹ 1.5

Profit %=ProfitC.P.×100%=1.57.5×100%=1507.5%=150075%=20%\text{Profit \%} = \dfrac{\text{Profit}}{\text{C.P.}} \times 100\%\\[1em] = \dfrac{1.5}{7.5} \times 100\%\\[1em] = \dfrac{150}{7.5}\%\\[1em] = \dfrac{1500}{75}\%\\[1em] = 20\%

Hence, the profit percent = 20%20\%.

(ii) Profit on 1 article = ₹ 1.5

Lets suppose xx articles are sold to make the profit of ₹ 75.

Profit on xx articles = ₹ 75

No. of articles x Profit on 1 article = Total Profit

x×1.5=75x=751.5x=75015x=50⇒ x \times 1.5 = 75\\[1em] ⇒ x = \dfrac{75}{1.5}\\[1em] ⇒ x = \dfrac{750}{15}\\[1em] ⇒ x = 50

Hence, 50 articles need to be sold to make a profit of ₹ 75.

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