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Mathematics

Assertion (A): The discriminant of the quadratic equation x2+22x+1=0x^2 + 2\sqrt{2}x + 1 = 0 is greater than zero.

Reason (R): If the discriminant of a quadratic equation is greater than zero, the quadratic equation has real and distinct roots.

  1. Both A and R are true, and R is the correct explanation of A.

  2. Both A and R are true, but R is not the correct explanation of A.

  3. A is true, but R is false.

  4. A is false, but R is true.

Quadratic Equations

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Answer

Given,

x2+22x+1=0x^2 + 2\sqrt{2}x + 1 = 0

Comparing x2+22x+1=0x^2 + 2\sqrt{2}x + 1 = 0 with ax2 + bx + c = 0 we get,

a = 1, b = 222\sqrt{2} and c = 1.

We know that,

Discriminant (D) = b2 - 4ac = (22)2(2\sqrt{2})^2 - 4 × (1) × (1)

= 8 - 4 = 4; which is positive.

Since, D = 4 > 0, the discriminant is greater than zero.

So, Assertion (A) is true.

D > 0 Real and distinct roots

D = 0 Real and equal roots

D < 0 Imaginary roots

If Discriminant is grater than zero,

Real and distinct roots

So, Reason (R) is true.

Thus, Both A and R are true, but R is not the correct explanation of A.

Hence, option 2 is the correct option.

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