Chemistry
Calculate the volume occupied by 53.5 g of Cl2. [Cl = 35.5]
Mole Concept
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Answer
[1 mole = 1 gm mol. wt. and occupies 22.4 lit at s.t.p.]
gm mol. wt. of Cl2 = (35.5 x 2) = 71 g
1 mole of Cl2 = 1 gm mol. wt. and occupies 22.4 lit.
71 g of Cl2 occupies 22.4 lit [s.t.p.]
∴ Vol. occupied by 53.5 g of Cl2
Therefore, volume occupied by 53.5 g of Cl2 is 16.87 lit
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