KnowledgeBoat Logo
|

Mathematics

If different values of variable x are 9.8, 5.4, 3.7, 1.7, 1.8, 2.6, 2.8, 8.6, 10.5 and 11.1; find

(i) the mean x\overline{x}

(ii) the value of (xx)∑(x - \overline{x})

Statistics

40 Likes

Answer

(i) Given:

The observation are 9.8, 5.4, 3.7, 1.7, 1.8, 2.6, 2.8, 8.6, 10.5 and 11.1.

Mean = Sum of all observations Number of all observations \dfrac{\text{Sum of all observations }}{\text{Number of all observations }}

= 9.8+5.4+3.7+1.7+1.8+2.6+2.8+8.6+10.5+11.110\dfrac{9.8 + 5.4 + 3.7 + 1.7 + 1.8 + 2.6 + 2.8 + 8.6 + 10.5 + 11.1}{10}

= 5810\dfrac{58}{10}

= 5.8

Hence, the mean x\overline{x} = 5.8.

(ii)

xxxxx - \overline{x}
9.89.8 - 5.8 = 4
5.45.4 - 5.8 = -0.4
3.73.7 - 5.8 = -2.1
1.71.7 - 5.8 = -4.1
1.81.8 - 5.8 = -4
2.62.6 - 5.8 = -3.2
2.82.8 - 5.8 = -3
8.68.6 - 5.8 = 2.8
10.510.5 - 5.8 = 4.7
11.111.1 - 5.8 = 5.3

(xx)∑(x - \overline{x}) = 4 + (-0.4) + (-2.1) + (-4.1) + (-4) + (-3.2) + (-3) + 2.8 + 4.7 + 5.3

= 4 - 0.4 - 2.1 - 4.1 - 4 - 3.2 - 3 + 2.8 + 4.7 + 5.3

= 0

Hence, (xx)∑(x - \overline{x}) = 0.

Answered By

29 Likes


Related Questions