If x 4 - 5x 2 + 4 = 0; the values of x are : 1. 1 or 2 2. 1 or 2 3. -1 and 2 4. -2, -1, 1 or 2

Given, ⇒ x 4 - 5x 2 + 4 = 0 ⇒ x 4 - 4x 2 - x 2 + 4 = 0 ⇒ x 2 (x 2 - 4) - 1(x 2 - 4) = 0 ⇒ (x 2 - 1)(x 2 - 4) = 0 ⇒ x 2 - 1 = 0 or x 2 - 4 = 0 ⇒ x 2 = 1 or x 2 = 4 ⇒ x = or x = ⇒ x = 1 or x = 2. Hence, Option 2 is the correct option.

Mathematics

If x⁴ - 5x² + 4 = 0; the values of x are :
1 or 2
± 1 or ± 2
-1 and 2
-2, -1, 1 or 2

Quadratic Equations

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Answer

Given,

⇒ x⁴ - 5x² + 4 = 0

⇒ x⁴ - 4x² - x² + 4 = 0

⇒ x²(x² - 4) - 1(x² - 4) = 0

⇒ (x² - 1)(x² - 4) = 0

⇒ x² - 1 = 0 or x² - 4 = 0

⇒ x² = 1 or x² = 4

⇒ x = $\sqrt{1}$ or x = $\sqrt{4}$

⇒ x = ± 1 or x = ± 2.

Hence, Option 2 is the correct option.

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Mathematics

If x⁴ - 5x² + 4 = 0; the values of x are :
1 or 2
± 1 or ± 2
-1 and 2
-2, -1, 1 or 2

Quadratic Equations

Answer

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If x⁴ - 5x² + 4 = 0; the values of x are :
1 or 2
± 1 or ± 2
-1 and 2
-2, -1, 1 or 2

Use quadratic formula to solve:
3y + $\dfrac{5}{16y}$ = 2

From each of the following equations, find the value of constant 'k' so that each equation has real and equal roots.
(i) kx(x - 2) + 6 = 0
(ii) (k + 4)x² + (k + 1)x + 1 = 0

For equation $\dfrac{1}{x} + \dfrac{1}{x - 5} = \dfrac{3}{10}$ ; one value of x is :
$-\dfrac{5}{3}$
10
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5

Which of the following is correct for the equation $\dfrac{1}{x - 3} - \dfrac{1}{x + 5}$ = 1 ?
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x = 3 and x ≠ -5
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