Mathematics
Find the value of k for which the equation 3x2 - 6x + k = 0 has distinct and real roots.
Quadratic Equations
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Answer
Comparing 3x2 - 6x + k = 0 with ax2 + bx + c = 0 we get,
a = 3, b = -6 and c = k.
Since equations have distinct and real roots,
∴ D > 0
⇒ (-6)2 - 4.(3).(k) > 0
⇒ 36 - 12k > 0
⇒ 12k < 36
⇒ k < 3.
Hence, k < 3.
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