Mathematics
Prove the following identities, where the angles involved are acute angles for which the trigonometric ratios are defined:
2(sin6 θ + cos6 θ) - 3(sin4 θ + cos4 θ) + 1 = 0.
Trigonometric Identities
25 Likes
Answer
Solving L.H.S.,
⇒ 2[(sin2 θ)3 + (cos2 θ)3] - 3[(sin2 θ)2 + (cos2 θ)2] + 1
⇒ 2[(sin2 θ + cos2 θ)3 - 3sin2 θ cos2 θ(sin2 θ + cos2 θ)] - 3[(sin2 θ + cos2 θ)2 - 2sin2 θ cos2 θ)] + 1
⇒ 2[(1)3 - 3sin2 θ cos2 θ(1)] - 3[(1)2 - 2sin2 θ cos2 θ)] + 1
⇒ 2 - 6sin2 θ cos2 θ - 3 + 6sin2 θ cos2 θ + 1
⇒ 2 - 3 + 1 - 6sin2 θ cos2 θ + 6sin2 θ cos2 θ
⇒ 3 - 3
⇒ 0.
Since, L.H.S. = R.H.S. hence, proved that 2(sin6 θ + cos6 θ) - 3(sin4 θ + cos4 θ) + 1 = 0.
Answered By
15 Likes
Related Questions
Prove the following identities, where the angles involved are acute angles for which the trigonometric ratios are defined:
.
Prove the following identity, where the angles involved are acute angles for which the trigonometric ratios are defined:
If cot θ + cos θ = m and cot θ - cos θ = n, then prove that (m2 - n2)2 = 16 mn.
When 0° < θ < 90°, solve the following equation:
2 cos2 θ + sin θ - 2 = 0