Ramesh invests ₹ 12800 for three years at the rate of 10% per annum compound interest. Find :

(i) the sum due to Ramesh at the end of the first year.

(ii) the interest he earns for the second year.

(iii) the total amount due to him at the end of third year.

(i) For first year :

P = ₹ 12800

R = 10%

T = 1 year

I = $\dfrac{P \times R \times T}{100} = \dfrac{12800 \times 10 \times 1}{100}$ = ₹ 1280.

Amount = P + I = ₹ 12800 + ₹ 1280 = ₹ 14080.

Hence, sum due at the end of first year = ₹ 14080.

(ii) For second year :

P = ₹ 14080

R = 10%

T = 1 year

I = $\dfrac{P \times R \times T}{100} = \dfrac{14080 \times 10 \times 1}{100}$ = ₹ 1408.

Hence, interest for second year = ₹ 1408.

(iii) Amount at end of second year = P + I = ₹ 14080 + ₹ 1408 = ₹ 15488.

For third year :

P = ₹ 15488

R = 10%

T = 1 year

I = $\dfrac{P \times R \times T}{100} = \dfrac{15488 \times 10 \times 1}{100}$ = ₹ 1548.80

Amount = P + I = ₹ 15488 + ₹ 1548.80 = ₹ 17036.80

Hence, amount due at end of third year = ₹ 17036.80