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Mathematics

The cost of a machine depreciated by ₹ 4000 during the first year and by ₹ 3600 during the second year. Calculate :

(i) the rate of depreciation.

(ii) the original cost of the machine.

(iii) its cost at the end of third year.

Compound Interest

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Answer

(i) Difference between depreciation in value between the first and second years is ₹ 4,000 - ₹ 3,600 = ₹ 400

So, the depreciation of one year on ₹ 4,000 = ₹ 400

By formula,

Rate of depreciation = 100×IP×T=100×4004000×1\dfrac{100 \times I}{P \times T} = \dfrac{100 \times 400}{4000 \times 1} = 10%.

Hence, rate of depreciation = 10%.

(ii) Let cost of machine be ₹ x.

Given,

Depreciation in first year = ₹ 4000

Depreciation % = 10%

x×1×10100=4000\therefore \dfrac{x \times 1\times 10}{100} = 4000

x = 40000.

Hence, original cost of machine = ₹ 40000.

(iii) Value of machine at beginning of third year = Original value - Depreciation in first and second years

= ₹ 40000 - (₹ 4000 + ₹ 3600)

= ₹ 40000 - ₹ 7600

= ₹ 32400.

For third year :

P = ₹ 32400

T = 1 year

Depreciation % = 10%

Depreciation = P×R×T100=32400×10×1100\dfrac{P \times R \times T}{100} = \dfrac{32400 \times 10 \times 1}{100} = ₹3240.

Value at the end of third year = ₹ 32400 - ₹ 3240 = ₹ 29160.

Hence, value of machine at the end of third year = ₹ 29160.

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