Solve the following equation using the formula :

x² + 2x - 6 = 0

Comparing x² + 2x - 6 = 0 with ax² + bx + c = 0 we get,

a = 1, b = 2, c = -6.

We know that,

x = $\dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Substituting values we get,

$\Rightarrow x = \dfrac{-(2) \pm \sqrt{(-2)^2 - 4(1)(-6)}}{2(1)} \\[1em] = \dfrac{-2 \pm \sqrt{4 + 24}}{2} \\[1em] = \dfrac{-2 \pm \sqrt{28}}{2} \\[1em] = \dfrac{-2 \pm 2\sqrt{7}}{2} \\[1em] = -1 \pm \sqrt{7}$

Hence, x = $-1 \pm \sqrt{7}$.