Chemistry
State your observations:
(a) HCl gas is passed through lead nitrate solution and the mixture is heated.
(b) Hydrochloric acid is added to silver nitrate solution.
(c) Ammonium hydroxide solution is added to the resultant product of part (b).
Hydrogen Chloride
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Answer
(a) When HCl gas is passed through lead nitrate, white precipitate of lead chloride is formed.
Pb(NO3)2 + 2HCl ⟶ PbCl2 ↓ + 2HNO3
(b) Hydrochloric acid, when reacted with silver nitrate solution it gives a thick curdy white precipitate of silver chloride. This white precipitate is insoluble in nitric acid.
AgNO3 + HCl ⟶ AgCl ↓ + HNO3
(c) On addition of ammonium hydroxide, the resultant of part (b) i.e., thick curdy white precipitate of silver chloride dissolves and forms a complex salt called diammine silver (I) chloride.
AgCl + 2NH4OH ⟶ [Ag(NH3)2Cl)] + 2H2O
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Related Questions
Study the figure given below and answer the questions that follow :
(i) Identify the gas Y.
(ii) What property of gas Y does this experiment demonstrate?
(iii) Name another gas which has the same property and can be demonstrated through this experiment.
Refer to the diagram given below and write balanced equations with conditions, if any, for the following conversions P to S.
Distinguish by using HCl.
(a) Lead nitrate solution and silver nitrate solution.
(b) Potassium sulphite and potassium sulphide.
The following questions pertain to the laboratory preparation of hydrogen chloride gas:
(i) Write the equation for it's preparation mentioning the condition required.
(ii) Name the drying agent used in the above preparation and give a reason for the choice.
(iii) State a safety precaution taken during the preparation of hydrochloric acid.