26, x + 4, x + 2 and 18 are in descending order of their values and their median is 20, then the value of x is :

1. 19

2. 17

3. 15

4. 13

Statement 1: For n number of data in a set, median = $\Big(\dfrac{n}{2}\Big)^{th}$ term.

Statement 2: If n is even, median = $\dfrac{1}{2}\Big[\Big(\dfrac{n}{2}\Big)^{th} \text{ term } + \Big(\dfrac{n}{2}+ 1\Big)^{th} \text{ term }\Big]$

1. Both the statements are true.

2. Both the statements are false.

3. Statement 1 is true, and statement 2 is false.

4. Statement 1 is false, and statement 2 is true.

Assertion (A): The mean of x₁, x₂ and x₃ is m. Then the value of (x₁ - m) + (x₂ - m) + (x₃ - m) = 0.

Reason (R): x₁ + x₂ + x₃ = 3m

⇒ (x₁ - m) + (x₂ - m) + (x₃ - m) = (x₁ + x₂ + x₃) - 3m

1. A is true, but R is false.

2. A is false, but R is true.

3. Both A and R are true, and R is the correct reason for A.

4. Both A and R are true, and R is the incorrect reason for A.

Assertion (A): Mean of n observations is x and mean of another set of n observations is y, the combined mean of all the observations is $\dfrac{x + y}{2}$

Reason (R): Total number of observations = nx + ny

∴ Mean of all the observations = $\dfrac{nx + ny}{2n}$

1. A is true, but R is false.

2. A is false, but R is true.

3. Both A and R are true, and R is the correct reason for A.

4. Both A and R are true, and R is the incorrect reason for A.