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Mathematics

Statement 1: ₹ (x3 - x) is spent in buying some identical articles at ₹ (x - 1) each. Number of articles bought = x3xx1\dfrac{x^3 - x}{x - 1}

Statement 2: Number of articles bought = x3xx1=x(x1)(x+1)x1=x2+x\dfrac{x^3 - x}{x - 1} = \dfrac{x(x - 1)(x + 1)}{x - 1} = x^2 + x

  1. Both the statements are true.

  2. Both the statements are false.

  3. Statement 1 is true, and statement 2 is false.

  4. Statement 1 is false, and statement 2 is true.

Factorisation

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Answer

Given, cost of each article = ₹ (x - 1)

Total cost = ₹ (x3 - x)

No. of articles bought=Total costCost of each article=x3xx1=x(x21)x1=x(x212)x1=x(x1)(x+1)x1=x(x+1)=x2+x.\Rightarrow \text{No. of articles bought} = \dfrac{\text{Total cost}}{\text{Cost of each article}} \\[1em] = \dfrac{x^3 - x}{x - 1}\\[1em] = \dfrac{x(x^2 - 1)}{x - 1}\\[1em] = \dfrac{x(x^2 - 1^2)}{x - 1}\\[1em] = \dfrac{x(x - 1)(x + 1)}{x - 1}\\[1em] = x(x + 1)\\[1em] = x^2 + x.

∴ Both the statements are true.

Hence, option 1 is the correct option.

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