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Study the diagram given below and answer the questions that follow :

Study the diagram given below and answer the questions that follow. ICSE 2025 Physics Solved Question Paper.

(a) Name the process depicted in the diagram.

(b) What is the value of X?

(c) Identify Y, the missing product of the reaction.

Radioactivity

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Answer

(a) Nuclear fission.

(b) X = 236

(c) As, the mass number and atomic number is conserved in the reaction then

From conservation of mass number

Let, mass number of Y be y.

mass number of neutron + mass number of 92235U_{92}^{235}\text{U} = 3 x mass number of Y + mass number of 3689Kr_{36}^{89}\text{Kr} + mass number of 56144Ba_{56}^{144}\text{Ba}

1+235=3×y+89+144⇒236=3y+233⇒3y=236−233=3⇒y=33=11 + 235 = 3 \times \text y + 89 + 144 \\[1em]

⇒ 236 = 3\text y + 233 \\[1em]

⇒ 3\text y = 236 - 233 = 3 \\[1em]

⇒ \text y = \dfrac{3}{3}=1

So, mass number of Y is 3.

From conservation of atomic number

Let, atomic number of Y be z.

atomic number of neutron + atomic number of 92235U_{92}^{235}\text{U} = atomic number of Y + atomic number of 3689Kr_{36}^{89}\text{Kr} + atomic number of 56144Ba_{56}^{144}\text{Ba}

⇒92+0=z+36+56⇒92=z+92⇒z=92−92=0⇒ 92 + 0 = \text z + 36 + 56 \\[1em] ⇒ 92 = \text z + 92 \\[1em] ⇒ \text z = 92 - 92 = 0 \\[1em]

As mass number of Y is 1 and it's atomic number is zero which is a property of a neutron.

Hence, Y is a neutron.

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