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Mathematics

The table below shows the daily expenditure on food of 25 households in a locality.

Daily expenditure (in ₹)Number of households
100 - 1504
150 - 2005
200 - 25012
250 - 3002
300 - 3502

Find the mean daily expenditure on food by a suitable method.

Statistics

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Answer

We will use step deviation method to find the mean.

In the following table a is the assumed mean and h is the class size.

Here, h = 50.

By formula,

Class mark = Upper limit + Lower limit2\dfrac{\text{Upper limit + Lower limit}}{2}

Daily expenditure (in ₹)Number of households (fi)Class mark (xi)di = xi - aui = (xi - a)/hfiui
100 - 1504125-100-2-8
150 - 2005175-50-1-5
200 - 25012a = 225000
250 - 30022755012
300 - 350232510024
TotalΣfi = 25Σfiui = -7

By formula,

Mean = a + ΣfiuiΣfi×h\dfrac{Σfiui}{Σf_i} \times h

Substituting values we get :

Mean =225+725×50=225+(14)=211\text{Mean } = 225 + \dfrac{-7}{25} \times 50 \\[1em] = 225 + (-14) \\[1em] = 211

Hence, mean daily expenditure on food = ₹ 211.

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