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Chemistry

(a) The vapour density of a gas is 8. What would be the volume occupied by 24.0 g of the gas at STP?

(b) A vessel contains X number of molecules of hydrogen gas at a certain temperature and pressure. How many molecules of nitrogen gas would be present in the same vessel under the same conditions of temperature and pressure?

Stoichiometry

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Answer

(a)

Given, V.D. = 8

Gram molecular mass = V.D. x 2 = 8 x 2 = 16 g.

16 g occupies 22.4 lit.

∴ 24 g. will occupy = 22.416\dfrac{22.4}{16} x 24 = 33.6 lit.

Hence, volume occupied by gas = 33.6 lit.

(b) According to Avogadro's law, equal volume of all gases under similar conditions of temperature and pressure contain equal number of molecules.

Hence, number of molecules of N2 = Number of molecules of H2 = X

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