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Chemistry

What do you observe when —

(i) Ammonia is passed over heated copper oxide.

(ii) Conc. H2SO4 is added to blue vitriol.

(iii) Acetylene is passed into bromine water.

(iv) NaCl is added to silver nitrate solution.

(v) Conc. HCl acid is exposed to atmosphere.

Ammonia

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Answer

(i) Ammonia gas reduces black copper [II] oxide to brown Copper.

2NH3 + 3CuO ⟶ 3Cu + 3H2O + N2

(ii) Blue hydrated copper sulphate becomes white anhydrous copper sulphate

CuSO4.5H2OConc. H2SO4CuSO4+5H2O\text{CuSO}4.5\text{H}2\text{O} \xrightarrow{\text{Conc. H}2 \text{SO}4} \text{CuSO}4 + 5\text{H}2\text{O}

(iii) Reddish brown bromine dissolved in water turns colourless when acetylene (ethyne) is passed through it.

C2H2 + Br2 ⟶ C2H2Br2 + Br2 ⟶ C2H2Br4

(iv) NaCl reacts with silver nitrate solution to form a white ppt.

NaCl + AgNO3 ⟶ AgCl ↓ [white ppt.] + NaNO3

(v) Due to strong affinity for water, concentrated hydrochloric acid pulls moisture from the air towards itself. This moisture forms droplets of water and hence, a cloud can be seen.

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