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Chemistry

Calculate the following :

The volume at s.t.p. occupied by a gas 'Y' originally occupying 760 cc. at 300 K and 70 cm. press, of Hg.

Gas Laws

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Answer

Initial conditionsFinal conditions [S.t.p.]
P1 = Initial pressure of the gas = 70 cm.P2 = Final pressure of the gas = 76 cm
V1 = Initial volume of the gas = 760 cc.V2 = Final volume of the gas = ?
T1 = Initial temperature of the gas = 300 KT2 = Final temperature of the gas = 273 K

By Gas Law:

P1×V1T1=P2×V2T2\dfrac{\text{P}1\times\text{V}1}{\text{T}1} = \dfrac{\text{P}2\times\text{V}2}{\text{T}2}

Substituting the values :

70×760300=76×V2273V2=760×70×273300×76V2=637 cc.\dfrac{70 \times 760}{300} = \dfrac{76\times\text{\text{V}}2}{273} \\[1em] \text{V}2 =\dfrac{760\times 70 \times 273}{300\times 76} \\[1em] \text{V}_2 = 637 \text{ cc.}

Therefore, final volume of the gas = 637 cc.

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