Chemistry
Calculate the molecular mass of the following :
(i) Na2SO4.10H2O
(ii) (NH4)2CO3
(iii) (NH2)2CO
(iv) Mg3N2
Given atomic mass of Na = 23, H = 1, O = 16, C = 12, N = 14, Mg = 24, S = 32
Relative Atomic Mass
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Answer
(i) Molecular mass of Na2SO4.10H2O
= 2 x 23 + 32 + 4 x 16 + 10(2 x 1 + 16)
= 46 + 32 + 64 + 180
= 322 amu
(ii) Molecular mass of (NH4)2CO3
= 2(14 + 4 x 1) + 12 + 3 x 16
= 36 + 12 + 48
= 96 amu
(iii) Molecular mass of (NH2)2CO
= 2(14 + 2 x 1) + 12 + 16
= 32 + 12 + 16
= 60 amu
(iv) Molecular mass of Mg3N2
= 3 x 24 + 2 x 14
= 72 + 28
= 100 amu
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