Chemistry
Calculate the relative molecular masses of
(a) CHCl3
(b) (NH4)2Cr2O7
(c) CuSO4.5H2O
(d) (NH4)2SO4
(e) CH3COONa
(f) Potassium chlorate, KClO3
(g) Ammonium chloroplatinate, (NH4)2PtCl6
[At. mass : C = 12, H = 1, O = 16, Cl = 35.5, N = 14, Cu = 63.5, S = 32, Na = 23, K = 39, Pt = 195, Ca = 40, P = 31, Mg = 24, Cr = 52]
Relative Atomic Mass
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Answer
(a) The relative molecular mass of CHCl3
= 12 + 1 + 3 x 35.5
= 12 + 1 + 106.5
= 119.5 amu
(b) The relative molecular mass of (NH4)2Cr2O7
= 2(14 + 4 x 1) + 2 x 52 + 7 x 16
= 36 + 104 + 112
= 252 amu
(c) The relative molecular mass of CuSO4.5H2O
= 63.5 + 32 + 4 x 16 + 5(2 x 1 + 16)
= 63.5 + 32 + 64 + 90
= 249.5 amu
(d) The relative molecular mass of (NH4)2SO4
= 2(14 + 4 x 1) + 32 + 4 x 16
= 36 + 32 + 64
= 132 amu
(e) The relative molecular mass of CH3COONa
= 12 + 3 + 12 + 16 + 16 + 23
= 82 amu
(f) The relative molecular mass of KClO3
= 39 + 35.5 + 3 x 16
= 39 + 35.5 + 48
= 122.5 amu
(g) The relative molecular mass of (NH4)2PtCl6
= 2(14 + 4 x 1) + 195 + 6 x 35.5
= 36 + 195 + 213
= 444 amu
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