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Mathematics

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Incase of regular polygon, with:

no. of sideseach exterior angleeach interior angle
(i) ..8……………………………………
(ii)..12…..…………………………
(iii) ……………..72°……….……………
(iv) ……………..45°……….……………
(v) …………………………….150°…….
(vi) …………………………….140°…….

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Answer

(i) As per the properties of polygon, if there are n number of sides then each of its exterior angles is 360°n\dfrac{360°}{n}.

n = 8

360°8\dfrac{360°}{8} = 45°

Hence, each exterior angle = 45°.

As per the properties of polygon, if there are n number of sides then each of its interior angles is (2n4)90°n\dfrac{(2n - 4)90°}{n}.

= (2×84)×90°8\dfrac{(2 \times 8 - 4) \times 90°}{8}

= (164)×90°8\dfrac{(16 - 4) \times 90°}{8}

= 12×90°8\dfrac{12 \times 90°}{8}

= 1080°8\dfrac{1080°}{8}

= 135°

Hence, each interior angle = 135°.

(ii) As per the properties of polygon, if there are n number of sides then each of its exterior angles is 360°n\dfrac{360°}{n}.

n = 12

360°12\dfrac{360°}{12} = 30°

Hence, each exterior angle = 30°.

As per the properties of polygon, if there are n number of sides then each of its interior angles is (2n4)90°n\dfrac{(2n - 4) 90°}{n}.

= (2×124)×90°12\dfrac{(2 \times 12 - 4) \times 90°}{12}

= (244)×90°12\dfrac{(24 - 4) \times 90°}{12}

= 20×90°12\dfrac{20 \times 90°}{12}

= 1800°12\dfrac{1800°}{12}

= 150°

Hence, each interior angle = 150°.

(iii) As per the properties of polygon, if there are n number of sides then each of its exterior angles is 360°n\dfrac{360°}{n}.

Exterior angle = 72°

360°n\dfrac{360°}{n} = 72°

⇒ n = 360°72°\dfrac{360°}{72°}

⇒ n = 5

Hence, number of sides = 5.

As per the properties of polygon, if there are n number of sides then each of its interior angles is (2n4)×90°n\dfrac{(2n - 4) \times 90°}{n}.

n = 5

= (2×54)×90°5\dfrac{(2 \times 5 - 4) \times 90°}{5}

= (104)×90°5\dfrac{(10 - 4) \times 90°}{5}

= 6×90°5\dfrac{6 \times 90°}{5}

= 540°5\dfrac{540°}{5}

= 108°

Hence, each interior angle = 108°.

(iv) As per the properties of polygon, if there are n number of sides then each of its exterior angles is 360°n\dfrac{360°}{n}.

Exterior angle = 45°

360°n\dfrac{360°}{n} = 45°

⇒ n = 360°45°\dfrac{360°}{45°}

⇒ n = 8

Hence, number of sides = 8.

As per the properties of polygon, if there are n number of sides then each of its interior angles is (2n4)×90°n\dfrac{(2n - 4) \times 90°}{n}.

n = 8

= (2×84)×90°8\dfrac{(2 \times 8 - 4) \times 90°}{8}

= (164)×90°8\dfrac{(16 - 4) \times 90°}{8}

= 12×90°8\dfrac{12 \times 90°}{8}

= 1080°8\dfrac{1080°}{8}

= 135°

Hence, each interior angle = 135°.

(v) As per the properties of polygon, if there are n number of sides then each of its interior angles is (2n4)×90°n\dfrac{(2n - 4) \times 90°}{n}.

(2n4)×90°n\dfrac{(2n - 4) \times 90°}{n} = 150°

⇒ (2n - 4) x 90° = 150°n

⇒ 180°n - 360° = 150°n

⇒ 180°n - 150°n = 360°

⇒ 30°n = 360°

⇒ n = 360°30°\dfrac{360°}{30°}

⇒ n = 12

Hence, number of sides = 12.

As per the properties of polygon, if there are n number of sides then each of its exterior angles is 360°n\dfrac{360°}{n}

360°12\dfrac{360°}{12} = 30°

Hence, each exterior angle = 30°.

(vi) As per the properties of polygon, if there are n number of sides then each of its interior angles is (2n4)×90°n\dfrac{(2n - 4) \times 90°}{n}.

(2n4)×90°n\dfrac{(2n - 4) \times 90°}{n} = 140°

⇒ (2n - 4) x 90° = 140°n

⇒ 180°n - 360° = 140°n

⇒ 180°n - 140°n = 360°

⇒ 40°n = 360°

⇒ n = 360°40°\dfrac{360°}{40°}

⇒ n = 9

Hence, number of sides = 9.

As per the properties of polygon, if there are n number of sides then each of its exterior angles is 360°n\dfrac{360°}{n}.

360°9\dfrac{360°}{9} = 40°

Hence, each exterior angle = 40°.

no. of sideseach exterior angleeach interior angle
(i) 845°135°
(ii) 1230°150°
(iii) 572°108°
(iv) 845°135°
(v) 1230°150°
(vi) 940°140°

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