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Mathematics

Find the mode and the median of the following frequency distribution :

xf
101
114
127
135
149
153

Measures of Central Tendency

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Answer

xfCumulative frequency
1011
1145 (1 + 4)
12712 (5 + 7)
13517 (12 + 5)
14926 (17 + 9)
15329 (26 + 3)

From table,

14 has the highest frequency.

∴ Mode = 14.

Here, n = 29, which is odd.

Median = n+12\dfrac{n + 1}{2} th term

= 29+12=302\dfrac{29 + 1}{2} = \dfrac{30}{2} = 15th term.

From table,

13th to 17th term = 13.

Median = 13.

Hence, median = 13 and mode = 14.

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