Mechanical advantage is the ratio of load lifted by a machine to the effort applied. Every simple machine has a mechanical advantage. The effort and load of some machines are given. Calculate the MA of each machine.

Machine	Effort (N)	Load (N)	Mechanical Advantage
A	20	60
B	140	70
C	10	100
D	5	25
E	15	45
F	120	60

Draw a line graph of the given data. Take effort on X-axis and load on Y-axis.

As,

$\text {Mechanical Advantage (M.A.)} = \dfrac{\text {Load}}{\text {Effort}}$

For machine A

$\Rightarrow \text {M.A.} = \dfrac {60}{20}\\[1em] \Rightarrow \text {M.A.} = 3$

So, mechanical advantage of the machine A is 3.

For machine B

$\Rightarrow \text {M.A.} = \dfrac {70}{140}\\[1em] \Rightarrow \text {M.A.} = \dfrac{1}{2} = 0.5$

So, mechanical advantage of the machine B is 0.5.

For machine C

$\Rightarrow \text {M.A.} = \dfrac {100}{10}\\[1em] \Rightarrow \text {M.A.} = 10$

So, mechanical advantage of the machine C is 10.

For machine D

$\Rightarrow \text {M.A.} = \dfrac {25}{5}\\[1em] \Rightarrow \text {M.A.} = 5$

So, mechanical advantage of the machine D is 5.

For machine E

$\Rightarrow \text {M.A.} = \dfrac {45}{15}\\[1em] \Rightarrow \text {M.A.} = 3$

So, mechanical advantage of the machine E is 3.

For machine F

$\Rightarrow \text {M.A.} = \dfrac {60}{120}\\[1em] \Rightarrow \text {M.A.} = \dfrac{1}{2} = 0.5$

So, mechanical advantage of the machine F is 0.5.

On summarizing all results in the table :

The line graph of the given data is shown below :